NEX FULL SCREEN PRINTER VERSION HBACK Chapter 12, Problem 073 A uniform ladder i
ID: 1295323 • Letter: N
Question
NEX FULL SCREEN PRINTER VERSION HBACK Chapter 12, Problem 073 A uniform ladder is 13 m long and weighs 260 N. In the figure, the ladder leans against a vertical, frictionless wall at height h a 8.0 m abi the ground. A horizontal force F is applied to the ladder at distance d 1.4 m from its base (measured along the ladder. If force magnitude F- 49 N. what are (a (b)y-components of the force of the ground on the ladder? If Fa 150 N. what are (c)x (dy- components of the force of the ground on the ladder? (e) Suppose the coefficient of static friction between the ladder and the ground is 0.32 for what minimum value of the force magnitude F will the base of the ladder just barely startto move toward the wall? (a) Number Units b) Number Units (c) Number Units Version 4.12.2.6 2000-2014 John Wiley & Son nc. All Rights Reserved. A Division of John Wi & Sons, IncExplanation / Answer
sintheta = h/L = 8/13
theta = 38
net torque = 0
Fx*L*sintheta-W*(L/2)*costheta - F*d*sintheta = 0
Fx*13*sin38 - (260*6.5*cos38)-(49*1.4*sin38) = 0
a) Fx = 171.669 N
b) Fy = N = W = 260 N
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part c)
theta = 38
net torque = 0
Fx*L*sintheta-W*(L/2)*costheta - F*d*sintheta = 0
Fx*13*sin38 - (260*6.5*cos38)-(150*1.4*sin38) = 0
c) Fx = 182.54 N
d) Fy = N = W = 260 N
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Fx = u*N = 0.32*260
e) Fx = 83.2 N
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