How many moles of calcium carbonate are needed to produce 15.3 L of carbon dioxi

Question

How many moles of calcium carbonate are needed to produce 15.3 L of carbon dioxide according to the following reaction at 0 °C and 1 atm?
calcium carbonate (s) calcium oxide (s) + carbon dioxide(g)
moles calcium carbonate
How many moles of calcium carbonate are needed to produce 15.3 L of carbon dioxide according to the following reaction at 0 °C and 1 atm?
calcium carbonate (s) calcium oxide (s) + carbon dioxide(g)
moles calcium carbonate
How many moles of calcium carbonate are needed to produce 15.3 L of carbon dioxide according to the following reaction at 0 °C and 1 atm?
calcium carbonate (s) calcium oxide (s) + carbon dioxide(g)
moles calcium carbonate

Explanation / Answer

CaCO3(s) ------> CaO (s) + CO2(g)

Mole ratio of CaCO3 to CO2 is 1:1.

Use the ideal gas equation to calculate the moles of CO2.

Volume (V) CO2 is 15.3 L.

Pressure (P) = 1 atm

Temperature (T) = 00C = 273.15 K

Gas constant (R) = 0.08206 atm L/mol K.

Moles of CO2(n) = PV/RT = (1x15.3)/(0.08206x273) = 0.683 mol

So, the number of moles of CaCO3 needed is 0.683 moles.

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