. ELECTROCHEMISTRY -Designing a galvanic c… A chemist designs a galvanic cell th

Question

. ELECTROCHEMISTRY -Designing a galvanic c… A chemist designs a galvanic cell that uses these two half-reactions half-reaction MnO4 (aq)+2H2O(l)+3e- MnO2(s)+4OH-(aq) Cu" (aq)+e Cu (aq) Answer the following questions about this cell standard reduction potential Ered+0.59 v Erod+0.153 V Write a balanced equation for the half-reaction that happens at the cathode Write a balanced equation for the half-reaction that happens at the anode Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written, Do you have Yes enough information to calculate the cell voltage under standard conditions? ONo If you said it was possible to calculate the cell voltage, do so and enter your answerLV here. Round your answer to 2 significant digits

Explanation / Answer

a)

cathode is gain of e- so, choose the highest potential

MnO4-(aq) + 2H2O(l) + 3e- = MnO4(s) + 4OH-(aq)

b)

anode is loss of e-, choose the lwoest E°red; invert it and get the same e- as in cathode

3Cu+(aq) = 3Cu+2 + 3e-

c)

get full equation

3Cu+(aq) + MnO4-(aq) + 2H2O(l) + 3e- = MnO4(s) + 4OH-(aq)+3Cu+2(aq) + 3e-

simplify

3Cu+(aq) + MnO4-(aq) + 2H2O(l) = MnO4(s) + 4OH-(aq)+3Cu+2(aq)

d

yes, we have enough data

e.

E°cell = Ered -EOx = 0.59 - 0.153 = 0.437 V

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