6. 100 80 3 60 50 75 100 m/z Relative Abundance 2.0 2.9 m/z Relative Abundance 5

Question

6. 100 80 3 60 50 75 100 m/z Relative Abundance 2.0 2.9 m/z Relative Abundance 5.5 1.3 5.8 m/z 39.0 41.0 45.0 47.0 50.0 51.0 62.0 63.0 64.0 65.0 77.0 89.0 90.0 91.0 92.0 121.0 123.0 138.0 139.0 140.0 1.3 3.2 00.0 8.4 2.4 3.4 3.1 0.8 a. Identify the molecular ion: b. The strong peak at 91 (the base peak) represents the presence of what: c. The A2 line at m/z 140 is consistent with the presence of: Hint use the isotopic abundance. mfz 138-95.0296; mVz 140-4.4% isotopic abundance. d. What is the chemical formula/name of this compound?

Explanation / Answer

A. Molecular ion is m/z 138.

B. Base peak at m/z value 91 is due to benzyl cation (C6H5CH2+).

C.The ratio intensites of M and M+2 ions 95.02:4.4 indicates the presence of sulfur.

D.The formula of the compound is PhCH2SCH3, and name is Benzyl methyl sulfide.

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