6. -13 points MintroSta19 1.E. 125. My Notes • Ask Your Teacher There are two ma
ID: 3043011 • Letter: 6
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6. -13 points MintroSta19 1.E. 125. My Notes • Ask Your Teacher There are two major tests of readiness for college, the ACT and the SAT, ACT scores are reported on a scale from 1 to 36. The distribution of ACT scores are approximately Normal with mean K = 21.5 and standard deviation o = 5.4. SAT scores are reported on a scale from 600 to 2400. The SAT scores are approximately Normal with mean u = 1498 and standard deviation = 316. Joshua scores 18 on the ACT. Anthony scores 1010 on the SAT. Assuming that both tests measure the same thing, who has the higher score? Report the z-scores for both students. (Round your answers to two decimal places.) Joshua's score standardizes to z = Anthony's score standardizes to Z = Therefore, ---Select--has the higher score. 7. + -11 points MintroStat9 1.E.127. IMy Notes o Ask Your Teacher There are two major tests of readiness for college, the ACT and the SAT. ACT scores are reported on a scale from 1 to 36. The distribution of ACT scores are approximately Normal with mean L = 21.5 and standard deviation o = 5.4. SAT scores are reported on a scale from 600 to 2400. The SAT scores are approximately Normal with mean u = 1498 and standard deviation o = 316. Alyssa scores 20 on the ACT. Assuming that both tests measure the same thing, what score on the SAT is equivalent to Alyssa's ACT score? (Round your answer to a whole number.) 8. -11 points MintroSta19 1.E. 140. IMy Notes o Ask Your Teacher The quartiles of any distribution are the values with the cumulative proportion of 0.25 and 0.75. The percent of observations that are suspected outliers according to the 1.5x IQR rule is the same for any Normal distribution. What is this percent? (Round your answer to two decimal places.)Explanation / Answer
6)as zscre =(X-mean)/std deviation
Joshua z score =(18-21.5)/5.4 =-0.65
Anthony z score = =(1010-1498)/316 =-1.54
7)
equalent sat score =1498+(20-21.5)*316/5.4=1410
8)
outlier percentage =0.70%
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