A mixture of methanol and propyl acetate contains 25.0 wt% methanol a. Using a s

Question

A mixture of methanol and propyl acetate contains 25.0 wt% methanol

a. Using a single dimensional equation determine the g-moles of methanol in 200.0 kg of the mixture

b. the flow rate of propyl acetate in the mixture is to be 100.0 lb-mole/h. what must the mixture flow rate be in lbm/h?

3.22. A mixture of methanol and propyl acetate contains 25.0 wt% methanol. (a) Using a single dimensional equation, determine the g-moles of methanol in 200.0 kg of the mixture. (b) The flow rate of propyl acetate in the mixture is to be 100.0 lb-mole/h. What must the mixture flow rate be in Ibm/h? m211

Explanation / Answer

a)

methanol = CH3OH

propyl acetate = C5H10O2

mass = 200 kg = 200000 g

if 25% by mass is methanol

200000 * 0.25 = 50000 g of methanol

mol = mass/MW = 50000 /32 = 1562.5 g-mol of methanol

B)

change to mass:

0.25*100 = 25 lbmol of methanol / h

0.75*100 = 75 lbmol of propyl acetate/ h

mass of methanol = mol*MW = 25*32 = 800 lb/h

mass of propyl acetat = 75*102.131 = 7659.825 lb/h

102.131 lbmol of propyl acetate / h

total mass =800 + 7659.825 = 8459.825 lb /h

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