1. What does an increase in temperature do to the spontaneity of this reaction?

Question

1. What does an increase in temperature do to the spontaneity of this reaction? Explain your reasoning.Use the following data to answer questions 1 through 3. All data is tabulated at 25°C   

2. What is the temperature in °C at which this reaction’s spontaneity changes?

H°f, kJ/mol                   90.29              0                       51.71

S° , J/mol K                  210.65          223.0                   261.6

G°f, kJ/mol                  86.60               0                       66.07

Explanation / Answer

S°total = S°product - S°reactant

S°total = [2 x 261.6] - [ ( 2x210.65) + 223.0]

S°total = [523.2] - [644.3]

S°total= -121.1 J/mol K

S°total< 0 so reaction is non sponteneous at tis temperature

2. G° = H° - T S°total

sponteneous change G° < 0

0 = (-77.16) - T (-121.1)

77.16 = 121.1 T

T = 0.63 0C

for sponteneuos T < 0.63 0C

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