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± Common-Ion Effect on Solubility for a Metal Hydroxide AB(s)A+(aq)+B(aq) The ge

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Question

± Common-Ion Effect on Solubility for a Metal Hydroxide

AB(s)A+(aq)+B(aq)

The generic metal hydroxide M(OH)2 has Ksp = 8.25×1018. (NOTE: In this particular problem, because of the magnitude of the Ksp and the stoichiometry of the compound, the contribution of OH from water can be ignored. However, this may not always be the case.)

Part A

What is the solubility of M(OH)2 in pure water?

Express your answer with the appropriate units.

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Part B

What is the solubility of M(OH)2 in a 0.202 M solution of M(NO3)2?

Express your answer with the appropriate units.

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Chemistry 106 Summer 2016

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Homework Set #5

± Common-Ion Effect on Solubility for a Metal Hydroxide

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± Common-Ion Effect on Solubility for a Metal Hydroxide

Consider the dissolution of AB(s):

AB(s)A+(aq)+B(aq)

Le Châtelier's principle tells us that an increase in either [A+] or [B] will shift this equilibrium to the left, reducing the solubility of AB. In other words, AB is more soluble in pure water than in a solution that already contains A+ or B ions. This is an example of the common-ion effect.

The generic metal hydroxide M(OH)2 has Ksp = 8.25×1018. (NOTE: In this particular problem, because of the magnitude of the Ksp and the stoichiometry of the compound, the contribution of OH from water can be ignored. However, this may not always be the case.)

Part A

What is the solubility of M(OH)2 in pure water?

Express your answer with the appropriate units.

SubmitHintsMy AnswersGive UpReview Part

Part B

What is the solubility of M(OH)2 in a 0.202 M solution of M(NO3)2?

Express your answer with the appropriate units.

SubmitHintsMy AnswersGive UpReview Part

Provide FeedbackContinue

Explanation / Answer

M(OH)2   -----> M^2+(aq) + 2oH-(aq)

ksp = (2s)^2s = 4s^3

8.25*10^-18 = 4s^3

solubility = 1.28*10^-6 M

part B

ksp = (2s)^2*0.202 = 8.25*10^-18

s = solubility = 3.2*10^-9 M