« previous | 19 of 25 | next Exercise 7.37 Part A A small block with mass 0.0400
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« previous | 19 of 25 | next Exercise 7.37 Part A A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described What is the magnitude of the acceleration of the block when it is at the point az 0.28m062 m by the potential: eneray function U)(6.00 Express your answer with the appropriate units. a 13.8m Submit My Answers Give Up Incorrect: Try Again; 6 attempts remaining Part B What is the direction of the acceleration of the block when is atthe port -0.28 m· 082 m ? 52.34 ° counterclockwise from the +z- axis Submit My Answers Give Up Incorrect: Try Again; 6 attempts remainingExplanation / Answer
Given,
U = 6 x^2 - 3.8 y^3
A)the acceleration will be:
dU/dt = 12 x - 11.4 y^2
a = sqrt [ (12 x/m)^2 + (- 11.4 y^2/m)^2]
a = sqrt [(12 x 0.28/0.04)^2 + (11.4 x 0.62^2/0.04)^2] = 138.051 m/s^2
Hence, a = 138.051 m/s^2
B)alpha = tan^-1 (-11.4 x 0.62^2/12 x 0.28) = 52.58 + 180 = 128 deg
alpha = 128 deg
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