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« previous | 4 of 9 next » Part C Problem 18.24 - Enhanced - with Video Solution What is the number density of the oxygen? Express your answer using two significant figures A 25-cm-diameter cylinder that is 43 cm long contains 42 g of oxygen gas at 20° C You may want to review ( -pages 500-502) For help with math skills, you may want to review: n= 3.7×1025 m Submit My Answers Give Up All attempts used; correct answer displayed For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Air in warmed tire Part D What is the reading of a pressure gauge attached to the tank? Express your answer to two significant figures and include the appropriate units 200 Submit My Answers Give Up Incorrect; Try Again; 2 attempts remaining Provide Feedback Continue

Explanation / Answer

Ans:-

b)
Volume of the cylinder
= r^2 h
= (12.5)^2 * 40
= 6.25 liter

42g = 42/32 g-mol

As a chemical engineer, I am accustomed to use a thumb rule that 1 g-mole of an ideal gas occupies 22.4 liter at 0° C and 1 atm (101.325 kPa)

=> (42/32) g-mol will occupy
(42/32) * 22.4 * (273 + 20)/(273) liter at 20° C and 1 atm
= 31.55 liter

As the actual volume is 6.25 liter, its pressure will be
= (31.55/6.25) x 101.325 kPa
= 162.9 kPa. absolute
= 162.9 - 101.325 kPa gauge pressure
= 61.59 kPa gauge pressure.

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