Nutrition Each serving of Gerber Mixed Cereal for Baby contains 60 calories and

Question

Nutrition Each serving of Gerber Mixed Cereal for Baby contains 60 calories and 11 grams of carbohydrates. Each serving of Gerber Mango Tropical Fruit Dessert contains 80 calories and 21 grams of carbohydrates." If the cereal costs 300 per serving and the dessert costs 50c per serving, and you want to provide your child with at least 140 calories and at least 32 grams of carbohydrates, how can you do so at the least cost? (Fractions of servings are permitted. Nutrition Each serving of Gerber Mixed Cereal for Baby contains 60 calories. 10 grams of carbohydrates, and no Vitamin C. Each serving of Gerber Apple Banana Juice contain.-60 calories. 15 grams of carbohydrates, and 120 percent of the U.S. Recommended Daily Allowance (RDA)of Vitamin C for infants. The cereal costs 10c per serving and the juice costs 30c per serving. If you want to proved your child with it at least 120 calories, at least 25 grams of carbohydrates, and at least 60 percent of the U.S RDA of Vitamin C for infants, how can you do so at the least cost? t Fraction-, of are permitted.)

Explanation / Answer

25) answer

Let x represent the number of servings of Gerber Mixed Cereal for Baby
and y represent the number of servings of Gerber Mango Tropical Fruit Dessert.

Notation: I use the computer-programming symbols
>= for "greater than or equal to" and
<= for "less than or equal to".

We have the following constraints:
x >= 0 [we can't serve negative servings]
y >= 0
3x + 4y >= 7 [calories, simplified from 60x + 80y <= 140]
11x + 21y >= 32 [carbohydrates]

The graphs of the constraint inequalities define a "feasible region" where all of the inequalities are satisfied.
This region has vertices at the intersections of various pairs of its borderlines:

x=0 intersects 3x+4y=7 at (0,7/4) and 11x+21y=32 at (0,32/21).
7/4 > 32/21, so (0,7/4) is the point that meets both constraints.

y=0 intersects 3x+4y=7 at (7/3,0) and 11x+21y=32 at (32/11, 0).
7/3 < 32/11, so (32/11,0) is the point that meets both constraints.

(1,1) [intersection of 3x+4y=7 and 11x+21y=32]


So our feasible region is a portion of the first quadrant with lower boundaries excluding a concave quadrilateral near the origin. Its vertices are
(0,7/4), (1/1), and (32/11,0)

The cost function, in cents per serving, is
c = 30x + 50y

Think of this as an infinite family of parallel lines, each defined by a different constant value for c.
The lower the value of c, the lower the cost, and the lower the line representing that cost on the graph.

The line with the minimum cost will be the lowest one that just touches the feasible region. It will either pass through just one vertex, or it will run along one boundary line and pass through the vertices at both ends of that boundary.

So all we have to do is evaluate the cost (c) at each of the vertices, and we'll find the minimum cost.

c = 30x + 50y
At (0,7/4), c = 50 (7/4) = 350/4 = 87.5
At (1,1), c = 30 + 50 = 80
At (32/11,0), c = 30 (32/11) = about 87.27

Conveniently, we find that 1 serving of each item meets the nutritional requirements at minimum cost of 80 cents.

Hey these two questions will take more than two hours to complete sorry friend my time is over with one question, i will try to update it soon meanwhile please try 26 by taking 25 solution as an example.

26 answer will be around 40 cents

Thank you.

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