1) A glass vessel calibrated to contain 9.76 mL at 4degree C was found to weigh
ID: 1002694 • Letter: 1
Question
1) A glass vessel calibrated to contain 9.76 mL at 4degree C was found to weigh 22.624 g when empty and dry. Filled with a soduim chloride (NaCl) solution at the same temperature , it was found to weigh 32.770 g. Calculate the solution's density.
2) the melting point of lauric acid and stearic acid are 43 degrees and 70 degrees C respectively. Are they solids liquids or gases at room temperature?
3) When water (d= 1.00/mL) and dichloromethane (d= 1.34 g/mL) are mixed, two layers are formed. which liquid is in the lower layer?
4) Which has the greater volume: 10g of hexane (d=0.66g/mL) or 10 g of toluene (d=0.87g/mL)? What is the voulme of each?
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Explanation / Answer
1) the density is the relation m/V where m is mass and V volume in the question we have a weigh of vessel = 22.624g and whit the NaCl of 32.770g the mass of NaCl = to 32.770g - 22.624g = 10.146g as the V is 9.76ml now calculate the density D = m/V = 10.146g/9.76ml = 1.04g/ml
2) the melting point is the temperature to the solid melt to your liquid form for example the melting poing of water is 0C over this T the water is liquid down this T the water is a solid in the question the melting poing are more high to 25C so to room temperature they are solid
3) de density is a relation m/V in a mix of nonsoluble liquid ever the sustance whit more high density is down in the question the dichloromethane have the high density so it s in the lower layer
4) the density is a relation m/V so D = m/V so if the mass is the same de density more low is the sustance than have the greater volume in the question the Hexane
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