1) A firefighter with a weight of 702 N slides down a vertical pole with an acce
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Question
1) A firefighter with a weight of 702 N slides down a vertical pole with an acceleration of 2.90 m/s2, directed downward. What are the magnitudes and directions (choose the positive direction up) of the vertical forces (a) on the firefighter from the pole and (b) on the pole from the firefighter?
2)Holding onto a tow rope moving parallel to a frictionless ski slope, a 63.1 kg skier is pulled up the slope, which is at an angle of 8.9
A firefighter with a weight of 702 N slides down a vertical pole with an acceleration of 2.90 m/s2, directed downward. What are the magnitudes and directions (choose the positive direction up) of the vertical forces (a) on the firefighter from the pole and (b) on the pole from the firefighter? Holding onto a tow rope moving parallel to a frictionless ski slope, a 63.1 kg skier is pulled up the slope, which is at an angle of 8.9 degree with the horizontal. What is the magnitude Frope of the force on the skier from the rope when (a) the magnitude v of the skier's velocity is constant at 2.36 m/s and (b) v = 2.36 m/s as v increases at a rate of 0.117 m/s2? An elevator cab that weighs 25.2 kN moves upward. What is the tension in the cable if the cab's speed is (a) increasing at a rate of 1.06 m/s2 and (b) decreasing at a rate of 1.06 m/s2? In Figure (a), a constant horizontal force is applied to block A, which pushes against block B with a 18.0 N force directed horizontally to the right. In Figure (b), the same force is applied to block B; now block A pushes on blockB with a 13.0 N force directed horizontally to the left. The blocks have a combined mass of 14.0 kg. What are the magnitudes of (a) their acceleration in Figure (a) and (b) force ? The figure shows a box of dirty money (mass m1 = 3.2 kg) on a frictionless plane inclined at angle ?1 = 31 degree . The box is connected via a cord of negligible mass to a box of laundered money (mass m2 = 1.1 kg) on a frictionless plane inclined at angle ?2 = 54 degree . The pulley is frictionless and has negligible mass. What is the tension in the cord? In the figure, a tin of anti-oxidants (m1 = 4.0 kg) on a frictionless inclined surface is connected to a tin of corned beef (m2 = 2.9 kg). The pulley is massless and frictionless. An upward force of magnitude F = 5.8 N acts on the corned beef tin, which has a downward acceleration of 4.1 m/s2. What are (a) the tension in the connecting cord and (b) angle ?? Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thrust) of 3430 N, the craft descends at constant speed; if the engine provides only 2360 N, the craft accelerates downward at 0.40 m/s2. (a) What is the weight of the landing craft in the vicinity of Callisto's surface? (b) What is the mass of the craft? (c) What is the magnitude of the free-fall acceleration near the surface of Callisto? The figure shows Atwood's machine, in which two containers are connected by a cord (of negligible mass) passing over a frictionless pulley (also of negligible mass). At time t = 0 container 1 has mass 1.2 kg and container 2 has mass 3.0 kg, but container 1 is losing mass (through a leak) at the constant rate of 0.22 kg/s. At what rate is the acceleration magnitude of the containers changing at (a)t = 0 and (b)t = 5 s? (c) When does the acceleration reach its maximum value? The figure shows a section of a cable-car system. The maximum permissible mass of each car with occupants is 2700 kg. The cars, riding on a support cable, are pulled by a second cable attached to the support tower on each car. Assume that the cables are taut and inclined at angle ? = 36 degree . What is the difference in tension between adjacent sections of pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline at 0.80 m/s2?Explanation / Answer
1. First let's draw a F.B.D of the firefighter. The firefighter must be pulling the pole down, thus, the pole will pull firefighter up therefore.
W - F = M a ( M is mass of firefighter, you can write M = W/g)
Or
F = W - W a / g => F = W [1 - a/g], this force is directed upwards i.e its on firefighter.
b)
The opposite and equal magnitude will be applied by firefighter on pole since the pole isn't moving.
Plug in the values. Make sure units are same for a and g.
2.
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