A compound has specific rotation of -39.0. A solution of the compound (0.187 g/m

Question

A compound has specific rotation of -39.0. A solution of the compound (0.187 g/mL) has an observed rotation of -6.52 degrees when placed in a polarimeter tube 10 cm long. What is the percent of each enantiomer in the solution? Please show all work thanks! A compound has specific rotation of -39.0. A solution of the compound (0.187 g/mL) has an observed rotation of -6.52 degrees when placed in a polarimeter tube 10 cm long. What is the percent of each enantiomer in the solution? Please show all work thanks!

Explanation / Answer

Solution

specific rotation of mixture = -39.0.

observed rotation of compound = -6.52

We know the equation for enantiomer in excess

ee = []obs / []max x 100 = -6.52/-39.0 * 100 = 2.564%

The major entantiomer I = ee + (100 – ee) / 2 = 2.564 + (100-2.546) = 51.27%

The minor entantiomer = (100 – ee) / 2 = (100 -2.546)/2 = 48.72%

Answer percent of each enantiomer in the solution

Major entantiomer I = 51.27%

Minor entantiomer = 48.72%

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