Answer the following questions regarding a solution of hexane and heptane that e

Question

Answer the following questions regarding a solution of hexane and heptane that exhibits ideal behavior Given at 25 degree C: p degree hexane and p degree heptane = 45.0 torr. by displaying your entire detailed caluculations determine the value of each of the following a) What will be the composition in terms of mole percentage of a hexane - heptane solution that has a vaopr pressure of 53.5 torr at 25 degree C? b) What will be the Partial Pressures in torr of the two components in the solution at 25 degree C? C) What will be the composition of the vapor at 25 degree C? Report the compostion in terms of mole percentages.

Explanation / Answer

a) Pohex = 64.0 torr

Pohept = 45.0 torr

Total pressure = P = 53.5 torr

P = xhex Pohex+ xhept Pohept

Mole fraction of hexane = xhex

mole fraction of heptane = xhept

xhex + xhept = 1

xhex= 1 - xhept

So, P = (1 - xhept) Pohex+ xhept Pohept

53.5 = (1 - xhept) 64.0 + xhept 45.0

53.5 = 64.0 - (64.0-45.0)xhept

53.5-64.0 = -19.0 xhept

-10.5 = -19.0 xhept

xhept = 10.5/19.0

xhept = 0.552

xhex = 1- 0.553 = 0.447

Mole percentage of hexane = xhex*100 = 44.7 %

Mole percentage of heptane = xhept*100 = 55.3 %

b) Partial pressure of hexane = Phex = xhex Pohex = 0.447 * 64.0 = 28.6 torr

Partial pressure of heptane = Phept = xhept Pohept = 0.553 * 45.0 = 24.9 torr

c) Composition of vapour:

moles of Hexane = Phex /P = 28.6/53.5 = 0.534

Mole percentage = moles of Hexane *100 = 0.534*100 = 53.4%

moles of Heptane = Phept /P = 24.9/53.5 = 0.466

Mole percentage = moles of Heptane *100 = 0.466*100 = 46.6%

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