a 2.00 liter sample of air at -50 degrees Celsius has a pressure of 700 torr. Wh
ID: 1000855 • Letter: A
Question
a 2.00 liter sample of air at -50 degrees Celsius has a pressure of 700 torr. What will be the new pressure a 2.00 liter sample of air at -50 degrees Celcius has a pressure of 700 torr. What will be the new pressure (torr) if the temperature is raised from 50 degrees Celsius and the volume is increased to 4.00 liters? I need a step-by-step clearly legible answer please thank you.
Explanation / Answer
This problem is based on Ideal gas equation stated as,
PV = nRT
PV/T = nR
R = molar gas constant.
For fixed moles of a gas i.e. n = constant.
Then,
PV/T = constant
Hence we can write,
P1V1/T1 = P2V2/T2 = ……….. = constant
Or,
P1V1/T1 = P2V2/T2 …………….(1)
Let initially, P1 = 700 torr, V1 = 2.00 L, T = –50 oC = –50 + 273.15 = 223.15 K.
And finally, P2 = ?, V2 = 4.00 L, T = 50 oC = 50 + 273.15 = 323.15 K
Note: As we are suppose to take ratios of all quantities we will not convert all in one unit as these units goinig to cancel out exactly. In case if not we would have converted all of them in one type of unit mainly SI or Litre – atm unis.
Let us put these values in eq.(2) and solve it for P2,
700 x 2.00 /223.15 = P2 x 4.00 /323.15
Let us re arrange it for P2,
P2 = 700 x (2.00/4.00) x (323.15/232.15)
P2 = 700 x ½ x 1.449
P2 = 350 x 1.449
P2 = 506.8 torr
P2 = 507 torr …………….(rounded)
Pressure will be 507 torr. (506 torr in option)
Answer: Option –(d).
=======================XXXXXXXXX=======================
I used direct way of calculation may because of that there is small difference in answer. But i don't think it will matter much.
On case please let me know.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.