Chemistry concepts and calculations
117302 questions • Page 353 / 2347
A .503 sample of limestone is dissoloved in acid and diluted to 2500 mL. A 25.0m
A .503 sample of limestone is dissoloved in acid and diluted to 2500 mL. A 25.0mL portion is pipetted into a 100.mL flask along with buffer, reducing agentm and the phen reagent. …
A .5121 g sample of a pure soluble chloride compound is dissolved in water, and
A .5121 g sample of a pure soluble chloride compound is dissolved in water, and all of the chloride ion is precipitated as AgCl by the addition of an excess of silver nitrate. The…
A 0,0000229 M sample of Compound X in a solvent has an absorbance of 0.241 at 52
A 0,0000229 M sample of Compound X in a solvent has an absorbance of 0.241 at 528 nm in a 1.000-cm cuvet. The solvent alone has an absorbance of 0.066. What is the molar absorptiv…
A 0.0020 mol sample of gas is held in a 1.0 L cylinder at 1 atm pressure and 20
A 0.0020 mol sample of gas is held in a 1.0 L cylinder at 1 atm pressure and 20 C. The cylinder is sealed with a piston, which allows for changes in volume and pressure. Pick corr…
A 0.0020mol sample of gas is held in a 1.0L cylinder at 1atm pressure and 20 deg
A 0.0020mol sample of gas is held in a 1.0L cylinder at 1atm pressure and 20 degrees C. The cylinder is sealed with a piston, which allows for changes in volume and pressure. for …
A 0.010 M solution of the weak acid, HB, is 1.0% ionized. K_a = ? a. 1.0 X 10^-6
A 0.010 M solution of the weak acid, HB, is 1.0% ionized. K_a = ? a. 1.0 X 10^-6 b. 3.3 X 10^-6 c. 5.0 X 10^-6 d. 1.0 X 106-3 e. none of these 25. Acid ionization constants for H_…
A 0.0100 L sample of H2SO4 was titrated with 0.150 M NaOH. It took 23.3 mL of Na
A 0.0100 L sample of H2SO4 was titrated with 0.150 M NaOH. It took 23.3 mL of NaOH from the buret--that's 0.0233 L--to reach the titration endpoint. 1) Balance the chemical equati…
A 0.0100 L sample of H2SO4 was titrated with 0.150 M NaOH. It took 23.3 mL of Na
A 0.0100 L sample of H2SO4 was titrated with 0.150 M NaOH. It took 23.3 mL of NaOH from the buret--that's 0.0233 L--to reach the titration endpoint. 1) Balance the chemical equati…
A 0.0100 mole sample of butane was burned in a bomb calorimeter. The heat from t
A 0.0100 mole sample of butane was burned in a bomb calorimeter. The heat from the reaction raised the temperature of 1.00 kg of water by 6.90 degree C. How much heat was released…
A 0.02000 L sample of 0.00483 M Zn2+ is titrated with 0.04061 L of 0.00683 M EDT
A 0.02000 L sample of 0.00483 M Zn2+ is titrated with 0.04061 L of 0.00683 M EDTA in a solution buffered to pH = 9.0. Calculate the concentration of Zn2+ in solution as the pZn2+.…
A 0.02350 M solution of NaCl in water is at 20degrees. The sample was created by
A 0.02350 M solution of NaCl in water is at 20degrees. The sample was created by dissolving a sample of NaCl in water and then bringing the volume up to 1.000 L. It was determined…
A 0.0287 M solution of a particular monoprotic weak acid. HA, has a pH of 5.99 a
A 0.0287 M solution of a particular monoprotic weak acid. HA, has a pH of 5.99 at 298 k. What is Delta G degree for the following equilibrium? HA(eq) + H_2O(l) dobluheadarrow H_3O…
A 0.035 mol sample of a weak acid, HA, is dissolved in 601 mL of water and titra
A 0.035 mol sample of a weak acid, HA, is dissolved in 601 mL of water and titrated with 0.41 M NaOH. After 33 mL of the NaOH solution has been added, the overall pH = 5.281. Calc…
A 0.050 M solution of pyruvic acid, an intermediate in metabolism, has a pH of 1
A 0.050 M solution of pyruvic acid, an intermediate in metabolism, has a pH of 1.91. Calculate K for pyruvic acid, a weak monoprotic acid. Use significant figures and “E” for scie…
A 0.0500 mol sample of a nutrient substance is burned in a bomb calorimeter cont
A 0.0500 mol sample of a nutrient substance is burned in a bomb calorimeter containing 2.00 x 10^2 H2O. If the formula weight of this nutrient substance is 114 g/mol, what is the …
A 0.0500-mol sample of a nutrient substance is burned in a bomb calorimeter cont
A 0.0500-mol sample of a nutrient substance is burned in a bomb calorimeter containing 2.00 X 10^2 g H2O. if the formula weight of this nutrient sunstanc is 114 g/mil, what is the…
A 0.0500-mol sample of a nutrient substance is burned in a bomb calorimeter cont
A 0.0500-mol sample of a nutrient substance is burned in a bomb calorimeter containing 2.00 Times 10^2 g H_2 O. If the formula weight of this nutrient substance is 114 g/mol, what…
A 0.08468 g sample of gas occupies 10.0-mL at 291.0 K and 1.10 atm. Upon further
A 0.08468 g sample of gas occupies 10.0-mL at 291.0 K and 1.10 atm. Upon further analysis, the compound is found to be 13.068% C and 86.932% Br. What is the molecular fo…
A 0.085 M solution of this substance is found to have a pH of 2.68. Calculate th
A 0.085 M solution of this substance is found to have a pH of 2.68. Calculate the Ka for this acid. Can you please show your work? I'm trying to understand.
A 0.085 M solution of this substance is found to have a pH of 2.68. Calculate th
A 0.085 M solution of this substance is found to have a pH of 2.68. Calculate the Ka for this acid. Can you please show your work? I'm trying to understand.
A 0.085 M solution of this substance is found to have a pH of 2.68. Calculate th
A 0.085 M solution of this substance is found to have a pH of 2.68. Calculate the Ka for this acid. Can you please show your work? I'm trying to understand.
A 0.1 M solution of styrene dissolved in toluene is stable for a much longer per
A 0.1 M solution of styrene dissolved in toluene is stable for a much longer period than a sample of pure styrene. The reason for this fact is: a. Styrene polymerizes faster than …
A 0.1 mole% caustic soda (NaOH) solution is to be concentrated in a continuous e
A 0.1 mole% caustic soda (NaOH) solution is to be concentrated in a continuous evaporator. The solution enters the unit at 25°C at a rate of 150 mol/min and is concentrated to 5 m…
A 0.10 M aqueous solution of a weak acid HA has a pH of 4.00. What is the values
A 0.10 M aqueous solution of a weak acid HA has a pH of 4.00. What is the values of K_c for HA? A) 1.1 times 10^-4 B) 1.0 times 10^-4 C) 1.0 times 10^-4 D) 1.0 times 10^-4 E) 1.0 …
A 0.100 M KCl solution is placed in contact with a 0.100M LiCl solution. which o
A 0.100 M KCl solution is placed in contact with a 0.100M LiCl solution. which of the following is true for junction between the solutions? a. HCl side of the junction will be pos…
A 0.100 M solution of an enantiomercially pure chiral compound D has an observed
A 0.100 M solution of an enantiomercially pure chiral compound D has an observed rotation of +.26 degree in a 1-dm sample container. The molar mass of the compount is 143.0 g/mol.…
A 0.100 M solution of an enantiomerically pure chiral compound D has an observed
A 0.100 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.16 degree in a 1-dm sample container. The molar mass of the compound is 120.0 g/mol…
A 0.100 M solution of an enantiomerically pure chiral compound D has an observed
A 0.100 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.16 degree in a 1-dm sample container. The molar mass of the compound is 120.0 g/mol…
A 0.100 M solution of an enantiomerically pure chiral compound D has an observed
A 0.100 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.16 degree in a 1-dm sample container. The molar mass of the compound is 120.0 g/mol…
A 0.100 M solution of an enantiomerically pure chiral compound D has an observed
A 0.100 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.14 degrees in a 1-dm sample container. The molar mass of the compounds is 140.0g/mo…
A 0.100 mole quantity of a monoprotic acid HA is added to 1.ooL of pure water. W
A 0.100 mole quantity of a monoprotic acid HA is added to 1.ooL of pure water. When equilibrium is reached, the pH of thesolution is 3.75. What is the value of Ka for theacid HA? …
A 0.100-L solution is made by dissolving 0.441 g of CaCl2( s ) in water. (a) Cal
A 0.100-L solution is made by dissolving 0.441 g of CaCl2(s) in water. (a) Calculate the osmotic pressure of this solution at 27 °C, assuming that it is completely dissociated int…
A 0.1002 g sample containing only CCl4 and CHCl3 was dissolved in methanol and e
A 0.1002 g sample containing only CCl4 and CHCl3 was dissolved in methanol and electrolyzed at the surface of a mercury electrode at –1.0 V, which required 50.20 s at a constant c…
A 0.102 g sample of an unknown compound was dissolved in 20.00 g of cyclohexane.
A 0.102 g sample of an unknown compound was dissolved in 20.00 g of cyclohexane. The resulting solution was found to have a freezing point of 5.63 degreeC. The freezing point of p…
A 0.102 g sample of an unknown compound was dissolved in 20.00 g of cyclohexane.
A 0.102 g sample of an unknown compound was dissolved in 20.00 g of cyclohexane. The resulting solution was found to have a freezing point of 5.63 degreeC. The freezing point of p…
A 0.109 g sample of an unknown gas occupies 112 mL at 100 degree C and 750 torr.
A 0.109 g sample of an unknown gas occupies 112 mL at 100 degree C and 750 torr. What is the molecular weight of the compound? 22.7 amu 30.2 amu 35.4 amu 47.5 amu 53.6 amu Oxygen …
A 0.10mol/l solution of propanoic acid (CH3CH2COOH) is pH 2.96.Calculate the Ka(
A 0.10mol/l solution of propanoic acid (CH3CH2COOH) is pH 2.96.Calculate the Ka(Acid dissociation Constant) and the percentdissociation for this acid. CH3CH2COOH + H2O <-> C…
A 0.110 M solution of an enantiomerically pure chiral compound D has an observed
A 0.110 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.26 in a 1-dm sample container. The molar mass of the compound is 150.0 g/mol. Map o…
A 0.1103 M KOH solution was used to titrate a 0.552 g sample of ascorbic acid (V
A 0.1103 M KOH solution was used to titrate a 0.552 g sample of ascorbic acid (Vitamin C) that was dissolved in 20 mL of water. The equivalence point occurred after 28.42 mL of th…
A 0.1105 g sample of primary standard grade Na2CO3 (M.M. = 105.99) was dissolved
A 0.1105 g sample of primary standard grade Na2CO3 (M.M. = 105.99) was dissolved in 55 mL of distilled H2O. The solution required 22.18 mL of the HCl solution to reach the methyl …
A 0.1105 g sample of primary standard grade Na2CO3 (M.M. = 105.99) was dissolved
A 0.1105 g sample of primary standard grade Na2CO3 (M.M. = 105.99) was dissolved in 55 mL of distilled H2O. The solution required 22.18 mL of the HCl solution to reach the methyl …
A 0.1156-g sample of a chlorocarbon compound was analyzed by burning it in oxyge
A 0.1156-g sample of a chlorocarbon compound was analyzed by burning it in oxygen and collecting the evolved gases in a solution of NaOH. After neutralizing, the sample was treate…
A 0.1164 g Zn-Al sample is dissolved in acid and gives 125.85 mL H2 gas when mea
A 0.1164 g Zn-Al sample is dissolved in acid and gives 125.85 mL H2 gas when measured over water at 22.8°C and 751.9 mm Hg barometric pressure. The vapor pressure of water is 21.0…
A 0.1195g sample of NA2CO3 was added to a 250ml flask, dissolved in 35ml of boil
A 0.1195g sample of NA2CO3 was added to a 250ml flask, dissolved in 35ml of boiled distilled water and 5 drops of phenolphthaline indicator added. Next, 40.00ml of an unknown HCl …
A 0.1195g sample of NA2CO3 was added to a 250ml flask, dissolved in 35ml of boil
A 0.1195g sample of NA2CO3 was added to a 250ml flask, dissolved in 35ml of boiled distilled water and 5 drops of phenolphthaline indicator added. Next, 40.00ml of an unknown HCl …
A 0.1195g sample of NA2CO3 was added to a 250ml flask, dissolved in 35ml of boil
A 0.1195g sample of NA2CO3 was added to a 250ml flask, dissolved in 35ml of boiled distilled water and 5 drops of phenolphthaline indicator added. Next, 40.00ml of an unknown HCl …
A 0.1195g sample of NA2CO3 was added to a 250ml flask, dissolved in 35ml of boil
A 0.1195g sample of NA2CO3 was added to a 250ml flask, dissolved in 35ml of boiled distilled water and 5 drops of phenolphthaline indicator added. Next, 40.00ml of an unknown HCl …
A 0.120 M solution of an enantiomerically pure chiral compound D has an observed
A 0.120 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.12 in a 1-dm sample container. The molar mass of the compound is 178.0 g/mol (a) Wh…
A 0.120 M solution of an enantiomerically pure chiral compound D has an observed
A 0.120 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.24 degree in a 1-dm sample container. The molar mass of the compound is 114.0 g/mol…
A 0.1270 g sample of solid acid is titrated with 28.21 mL of 0.1095 M NaOH. This
A 0.1270 g sample of solid acid is titrated with 28.21 mL of 0.1095 M NaOH. This overshot the endpoint and 2.51 mL of 0.1064 M HCl was used in the back titration. (Back Titration …
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