Print Calculator Periodic Table Calculator Question 16 of 17 ncorrect Map A plin

Question

Print Calculator Periodic Table Calculator Question 16 of 17 ncorrect Map A pling Uric acid dissociates as shown in the figure at HN N the right with a pKa of 5.80, and can be treated HN N as a monoprotic acid in this pH range. Its solubility in urine depends on the relative amount of protonated and unprotonated forms. A urine sample was found to have a pH of 6.30 HA What would be the ratio of the unprotonated form, A to the protonated form, HA, for uric acid in this urine sample? Number .32 HAI A Previous ® Give Up & View Solution Check Answer Next Ext O Hint

Explanation / Answer

PH = PKa + log[A-]/[HA]

6.3 = 5.8 + log[A-]/[HA]

log[A-]/[HA] = 6.3-5.8

log[A-]/[HA] = 0.5

[A-]/[HA]     = 100.5 = 3.162

[A-]/[HA]     = 3.162

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.