11-Spring16-EVANS Activities and Due Dates - HW 6 O 5/10/2016 11:55 PM 0 22.2/10

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11-Spring16-EVANS Activities and Due Dates - HW 6 O 5/10/2016 11:55 PM 0 22.2/1005/10/2016 04:26 PM Gra -Print Calculator ba Periodic Table Print Calulator Periodic Table Question 4 of 21 Mapa sapling:learna A sample of an ideal gas at 1.00 atm and a volume of 1.58 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure volume. When the pressure had increased to 20.0 atm, what was the volume of the sample? Assume that the temperature was heid constant. the balloon and reduced its Number about us careers partners prvacy poliqy 10

Explanation / Answer

The amount of moles of substance will be the same at any temperature and pressure because the ballon is closed.

So, let´s find that amount:

PV= nRT

n= PV/RT = 1atm x 1.58L/RT

this moles are the same as the moles at a pressure of 20 atm:

n= 20atm x V/RT

1atm x 1.58L/RT = 20atm x V/RT

The "RT" is at both sides so we can omit it:

1.58 = 20 xV ----> V= 0.079L

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