Determine the molar mass of each of the following gases: 0 76 g of a gas that oc

Question

Determine the molar mass of each of the following gases: 0 76 g of a gas that occupies 450 mL at 0 degree C and 1 00 atm (STP). Express your answer to two significant figures and include the appropriate units. 1.05 g of a gas that occupies 1 15 L at 0 degree C and 760 mmHg (STP). Express your answer to three significant figures and include the appropriate units. 1.39 g of a gas that occupies 1.30 L at 695 mmHg and 24 0 degree C. Express your answer to three significant figures and include the appropriate units. 3.1 g of a gas that occupies 2.5 L at 0 94 atm and 19 degree C. Express your answer to two significant figures and include the appropriate units. M = M =

Explanation / Answer

Molar mass = g x RT/PV

Part A : we have,

g = 0.76 g

R = gas constant

T = 0 + 273 = 273 K

P = 1 atm

V = 0.45 L

we get,

molar mass (M) = 0.76 x 0.08205 x 273/1 x 0.45 = 37.83 g/mol

Part B : we have,

g = 1.05 g

R = gas constant

T = 0 + 273 = 273 K

P = 760mmHg = 1 atm

V = 1.15 L

we get,

molar mass (M) = 1.05 x 0.08205 x 273/1 x 1.15 = 20.452 g/mol

Part C : we have,

g = 1.39 g

R = gas constant

T = 24 + 273 = 297 K

P = 695 mmHg = 0.9145 atm

V = 1.30 L

we get,

molar mass (M) = 1.39 x 0.08205 x 297/0.9145 x 1.30 = 28.492 g/mol

Part D : we have,

g = 3.1 g

R = gas constant

T = 19 + 273 = 292 K

P = 0.94 atm

V = 2.5 L

we get,

molar mass (M) = 3.1 x 0.08205 x 292/0.94 x 2.5 = 31.60 g/mol

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.