Lithium and nitrogen react in a combination reaction to produce lithium nitride:

Question

Lithium and nitrogen react in a combination reaction to produce lithium nitride:

6Li (s) + N2 (g) 2Li3N (s)

In a particular experiment, 4.50-g samples of each reagent are reacted. The theoretical yield of lithium nitride is ________ g.

Lithium and nitrogen react in a combination reaction to produce lithium nitride:

6Li (s) + N2 (g)  2Li3N (s)

In a particular experiment, 4.50-g samples of each reagent are reacted. The theoretical yield of lithium nitride is ________ g.

Explanation / Answer

In a particular experiment, 4.50-g samples of each reagent are reacted. The theoretical yield of lithium nitride is ________ g.

6Li (s) + N2 (g) 2Li3N (s)

mol of Li = mass/MW = 4.5/6.941 = 0.64832 mol of Li

mol of N2 = mass/MW = 4.5/28 = 0.1607142 mol of N2

verify:

0.64832 mol of Li requires = 0.64832/6 = 0.108053 mol of N2, therefore, Lithium limits

then, theoretical yield

1 mol of N2 = 2 mol of Li3Ni

0.108053 mol of N2 = 2x0.108053 = 0.216106 mol of Li3Ni

mass of Li3N = mol*Mw = (0.216106)*34.83 = 7.5269 g of LiN

from the list, choose D

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