determining a gas constant: given .0219 g MnO 2 and 2.3020 g KClO 3 the mass of
ID: 993540 • Letter: D
Question
determining a gas constant:
given .0219 g MnO2 and 2.3020 g KClO3 the mass of Oxygen generated is .0383 g. How many moles of Oxygen are generated?
Udated to show answer since the experts kept asking for more information that was not needed.
No...No data is missing...Idiots...it is not missing... .0383 grams divides by O2 molar mass of 32 (2 x 16) gives you moles of .001196875, after sig figs its .0012, idiots...no data is missing. I knew the answer when I posted I just wanted to see if someone could get it right....why am I paying for this crap...???
Explanation / Answer
Dear Friend i can understand your frustration. This is First time to see your question in my Q&A Tab. First of all i am very sorry from Experts side. Please be patient. Dont use harsh words like idiots & scounders in public and especially writing harsh words in not recommended for your bright future.
Yeah your calculation is absolutely correct
moles = weight of the substance / molar mass (both should be in grams only)
moles = 0.0383 / 32 = 0.0012 mol
0.0012 moles of Oxygen are generated
Thank you, excuse me for giving free advice
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