determine the reaction order for hcl using calculations described in the backgro

Question

determine the reaction order for hcl using calculations described in the background section. show your work. note that your answer will probably not be an even whole number as it is in the examples, so round to the nearest whole number.

Reaction Order and Rate Laws Name: (2pts) Exercise 1: Determining the Rate Laws of the Reaction between HCI and Na2S203 Data Table 1. Varying Concentrations of 1.0 M HCI. (8 pts) Reaction Reaction Reaction Time #of #of #of Stock Stock drops drops drops Solution Solution Rate ming in ming in (seconds) Hal H20|Nasel Napo,trial 1 Trial 2|Average Well # Hd NaMo, Ha determine the concentration after mixing, take the stock solution concentration drops d of that stock solution/total drops in the well. There are a total of 20 drops in the reaction RT A PICTURE OF YOUR WELL PLATE WITH sSOME OF THE WELLS COMPLETE. INCLUDE A E OF PAPER WITH YOUR NAME AND THE DATE ON IT. (10 pts) able 2. Varying Concentrations of 0.3 M Na 5203.(8pts) Concentrations Reaction Reaction #of #of #of Stock Stock (after latter drops drops drops Solution Solution miing in mixing in Reaction Time (seconds) well) HC HO Na,S,0 HCINa,S,0a HCI Na s,0 Trial 1 Trial 2 Average

Explanation / Answer

Rate = k [HCl]m

We have to find m

For this we use experimental observation of different runs.

      Concentration of HCl                Rate

Run 1          0.6 M                               0.043

Run 2               0.3 M                           0.034

Run 3               0.2 M                           0.027

Lets take ratio of rate of any of the two runs

Rate (Run 2) / Rate (run 3) = k [ HClm / k [HCl ]m

We know the k is rate constant. The k is same for all the runs since the reaction is same.

Lets plug the value of rates and concentration of corresponding runs.

0.034/0.027 = (0.3 M)m / (0.2 M)m

1.26 = (1.5 )m

Lets take ln of both side

Ln 1.26 = m ln 1.5

m = 0.6

The reaction order for HCl is 0.6

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