1) When heated, KClO3 decomposes into KCl and O2. 2KCl 3 ---> 2KCl +3O 2 If this

Question

1) When heated, KClO3 decomposes into KCl and O2.

2KCl3 ---> 2KCl +3O2

If this reaction produced 42.0 g of KCl, how much O2 was produced (in grams)?

2) Balance the following equations by inserting coefficients as needed.

C3H8+ O2 ---> CO2 + H20

N2H4 ---> NH3+ N2

3) The combustion of propane may be described by the chemical equation,

C3H8(g) + 5O2 (g) ---> 3CO2(g) + 3H2O (g)

How many grams of O2(g) are needed to completely burn 73.4 g of C3H8(g)?

4) If 7.43 moles of C5H12 reacts with excess O2, how many moles of CO2 will be produced in the following combustion reaction?

C5H12+ 8O2 --> 6H2O + 5CO2

Explanation / Answer

1.

mol of KCl = mass/MW

mol = 42/74.5513 =0.563 mol of KCl

rtio is

2:3

so

3/2*0.563 = 0.8445 mol of O2

mass = mol*MW = 0.8445*32 = 27.024 g of O2

NOTE: Please consider posting multiple questions in multiple set of Q&A.

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