A student titrates a KHSO 4 /H 2 C 4 H 2 O 4 mixture where (unbeknownst to the s

Question

A student titrates a KHSO4 /H2C4H2O4 mixture where (unbeknownst to the student) the concentration of the KHSO4 is smaller than that of H2C4H2O4. When analyzing the titration data the student assumes that half the volume used to reach the first equivalence point is used to enutralize the KHSO4 and the other half is used to neutralize the first proton of H2C4H2O4. This will result in a computer concentration of KHSO4 that is:
A) Correct
B) Incorrectly Low  
C) Incorrectly High
D) Not Enough Information

So, Im looking for an explanation here. I feel like the concentration would be less than half, but Im also not sure because without seeing the actual titration of the graph, I feel like its impossible to know. When we did this in lab the concentration of the monoprotic acid was less than the diprotic, and there were less moles etc. so Im thinking here that the student will come up with a value that is way too high. Are my assumptions correct, or is there something Im missing?

Explanation / Answer

Lets say the concentration of KHSO4 is half of H2C4H2O4. Volume required to reach first equivalence point for H2C4H2O4 is equal to neutralizing volume for KHSO3. The other volume part will react with H2C4H2O4 to reach first equivalence point.

With no change in volume by addition of reagent.

We would get,

A) correct

concentration of KHSO4

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