A student student works an experimental of 1 dimensional collision. In the elast

Question

A student student works an experimental of 1 dimensional collision. In the elastic collision, the following data table, fill the following the empty spaces. We try to calculate V1f. using with momentum conservation. Find your expectation value of V1f. Use the data in the first table. We try to calculate V2f. using with energy conservation. Find your expectation value of V1f. Use the data in the first table. In the perfectly inelastic collision, find the final velocity. In this inelastic collision, find the lost energy

Explanation / Answer

Given,

m1 = 280g, m2 = 180g, u1 = 0.5m/s , u2 = -0.25m/s, v2 = 0.66m/s

1)Using momentum conservation, m1*u1 + m2*u2 = m1*v1 + m2*v2

Thus, v1 = (m1*u1 + m2*u2 - m2*v2)/m1 = -0.085m/s

.

2)Using energy conservation, 0.5m1*u12 + 0.5m2*u22 = 0.5m1*v12 + 0.5m2*v22

Thus, v12 = (m1*u12 + m2*u22 - m2*v22)/m1 = 0.01m2/s2

v1 = 0.1m/s or -0.1m/s

.

3)In case of inelastic collision,

using conservation of momentum,

m1*u1 + m2*u2 = (m1+m2)*v => v = (m1*u1 + m2*u2)/(m1+m2) = -0.048m/s

.

4) Loss in energy = Initial Energy - Final Energy = 0.5m1*u12 +0.5m2*u22 -0.5(m1+m2)*v2 = 44.37 mJ

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