A UVivis light a standard r produced the following linear calibration equation f
ID: 986973 • Letter: A
Question
A UVivis light a standard r produced the following linear calibration equation for a give Map A = 0.653C + 0.0342 Concentration (M) Absorbance where C is the molar concentration, and A is the absorbance. The detector's lifetime was running out, so the lab manager replaced the detector. 0.10 0.20 0.30 0.40 0.0540 0.1258 0.1855 0.2445 0.0351 0.1000 0.1677 0.2303 detector and diffraction grating, a student measured different standard concentrations and nt thedata in the se tble to 0.50 the data in the second column of the table to 0.3610 0.4068 0.4731 0.5478 0.6279 0.6887 right. The lab manager aligned the detector and 0.2925 0.3052 0.3613 0.60 data was probably unreliable. The student retook the measurements and got the data in the third column of the table to the right. 0.80 0.90 0.6525 Find the linear calibration equation and the square of the correlation coefficient, R2, for each set of measurements. Before alignment: C+ After alignment: Next ExitExplanation / Answer
all what you have to do is plot Absorbance Vs Concentration, and you will get the calibration curve. Put Absorbance in the y axis and concentration in the x axis.
Doing so (I put the data in my calculator), the linear equation obtained was the following:
y = 0.05795 + 0.53109x That would be:
A = 0.53109C + 0.05795 R2 = 0.946921
Now, doing the same thing but after the alignment:
y = 0.03549 + 0.64608x That would be:
A = 0.64608C + 0.03549 R2 = 0.998216
Hope this helps
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