Saturated solid at -10 degree C encompasses the entire volume (0.32 cm^3) of a f

Question

Saturated solid at -10 degree C encompasses the entire volume (0.32 cm^3) of a free piston-cylinder arrangement. Atmospheric pressure is 100 Pa (i.e., the piston-cylinder arrangement is in a vacuum). It undergoes a sublimation process until the volume has increased by 1000. Determine: The pressure in [kPa] and specific volume in [m^3/kg] at State 1 Mass of solid at State I in [gm] The mass of solid and gas at State 2 in [gm] and the quality of the mixture. The mass of the piston in [kg] if its cross-sectional area is 0.8 m^2. The work done by the gas in [J] The heat added in [J] drawing the appropriate control volume Ignore the KE and PE of the solid and gas. Show all calculations and unit conversions otherwise no points will be given.

Explanation / Answer

a) The pressure in KPa

as 1 Pa = 0.001 KPa

So 100 Pa = 0.1 KPa

Assuming pressure is constant

b) Mass of solid = Mass of vapours

Final volume = 320cm^3

Specific volume =Volume / Mass = RT / P = 8.314 X 10^3 X (263) / 0.1 = 21865.82cm^3

Work done by gas = Pressure X change in volume = 0.1 X 320 cm^3 = 32 KPa cm^3 = 0.32 Joules

For other calculations need more information

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