A) 2A B + C The above reaction is run and it is found that a plot of the concent

Question

A) 2A B + C

The above reaction is run and it is found that a plot of the concentration of A versus time is linear as the reaction proceeds. This indicates that the reaction is ...

zero order in [A]

first order in [A]

second order in [A]

third order in [A]

B)2A B + C

The above reaction is run and it is found that a plot of the natural log of the concentration versus time is linear. This indicates that the reaction is ...

zero order in [A]

first order in [A]

second order in [A]

third order in [A]

zero order in [A]

first order in [A]

second order in [A]

third order in [A]

Explanation / Answer

This reaction is zero order since the data only fits to zero order integrated rate law.

Integrated rate law:

[A] = [A]0 – kt

Here y = [ A] and slope is -k , so when we plot concentration of A with respect to t then we get the equation in the form of line

y = mx + c

So the answer Zero order in [A]

B)

This reaction fits to first order reaction

Integrated rate equation for first order rate law.

ln [A]t = ln [A]0 -kt

when we plot ln [A]t Vs t then we get straight line.

So answer is :

First order with respect to A

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