A) 2H+(aq)+Fe(s)?H2(g)+Fe2+(aq) 1)Indicate the half-reaction occurring at Anode.

Question

A) 2H+(aq)+Fe(s)?H2(g)+Fe2+(aq)

1)Indicate the half-reaction occurring at Anode.

Express your answer as a chemical equation. Identify all of the phases in your answer.

2) Indicate the half-reaction occurring at Cathode.

Express your answer as a chemical equation. Identify all of the phases in your answer.

B) 2NO?3(aq)+8H+(aq)+3Cu(s)?2NO(g)+4H2O(l)+3Cu2+(aq)

1) Indicate the half-reaction occurring at Anode.

Express your answer as a chemical equation. Identify all of the phases in your answer.

2) Indicate the half-reaction occurring at Cathode.

Express your answer as a chemical equation. Identify all of the phases in your answer.

Explanation / Answer

A)

given reaction is

2H+ (aq) + Fe(S) ---> H2 (g) + Fe+2 (aq)

we can see that

Fe is oxidized to Fe+2

and

H+ is reduced to H2

now

we know that

oxidation takes place at anode

so

1) half reaction occuring at anode :

Fe(s) -----> Fe+2 (aq) + 2e-

now

reduction takes place at cathode

so

2) half reaction occuring at cathode :

2H+ (aq) + 2e- ----> H2 (g)

B)

given reaction is

2N03- (aq)   + 8H+ (aq) + 3 Cu (s) ----> 2 NO (g) + 4H20 (l) + 3 Cu+2 (aq)

we can see that

Cu is oxidized to Cu+2

also

N03- is reduced to NO

we know that

oxidation takes place at anode

so

1) half reaction occuring at anode :

Cu(s) ----> Cu+2 (aq) + 2e-

now

reduction takes place at cathode

so

2) half reaction occuring at cathode :

N03- (aq) + 4H+ (aq)   + 3e- ---> N0 (g) + 2H20 (l)

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