A solution of a compound called potassium acid phthlate (KHP), is prepared by di

Question

A solution of a compound called potassium acid phthlate (KHP), is prepared by dissolving 3 grams of KHP in 100 mLs of water. This solution is then reacted with exactly 14.47 mLs of a 1.015 M NaOH solution. Assume KHP reacts in a one-to-one ratio with NaOH, calculate the molar mass of KHP. A solution of a compound called potassium acid phthlate (KHP), is prepared by dissolving 3 grams of KHP in 100 mLs of water. This solution is then reacted with exactly 14.47 mLs of a 1.015 M NaOH solution. Assume KHP reacts in a one-to-one ratio with NaOH, calculate the molar mass of KHP.

Explanation / Answer

m = 3 g of KHP

V = 100 ml = 0.1 L

then

V = 14.47 ml of NaOH solution is used

M = 1.105 M of NaOh

assume

KHP + NaOH = KNaHP + H2O

therefore

mol of base = mol of acid

V acid = 14.47 ml = 0.01447

mol of base = Molarity * Volume = 1.015*0.01447 = 0.01468705 mol of Acid

then we have 1:1 ratio; 0.01468705 mol of base

We need molar mass so

MW = mass/mol = 3/0.01468705 = 204.2615 g /mol

which isw pretty near to the real value of KHP = 204.22

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