One of the successes of the Bohr model is the fact that it allowed \"mysterious\
ID: 985697 • Letter: O
Question
One of the successes of the Bohr model is the fact that it allowed "mysterious" lines observed in solar spectra to be assigned to He+. Recall that the Bohr model applies to any one-electron atomic species. Since He+ is a one-electron species, you can use the Bohr formula to determine the transition responsible for one of the lines observed from the helium discharge tube. This line occurs at 468.9 nm, and may be hard for you to see. Calculate the values of nf (n-final) and ni (n-initial) for this transition. Show all of the calculations you preformed to determine nf and ni. One of the successes of the Bohr model is the fact that it allowed "mysterious" lines observed in solar spectra to be assigned to He+. Recall that the Bohr model applies to any one-electron atomic species. Since He+ is a one-electron species, you can use the Bohr formula to determine the transition responsible for one of the lines observed from the helium discharge tube. This line occurs at 468.9 nm, and may be hard for you to see. Calculate the values of nf (n-final) and ni (n-initial) for this transition. Show all of the calculations you preformed to determine nf and ni.Explanation / Answer
We know that 1/ = Rz2 [ 1/n1^2- 1/n2^2]
= wavelength
R = Rydberg constant = 1.097 x 107 m-1
Z = atomic number
Atomic number of He, Z = 2
Given that = 468.9 nm = 468.9 x 10-9 m
1/ = Rz2 [ 1/n1^2- 1/n2^2]
1/ 468.9 x 10-9 m = 1.097 x 107 m-1 x 22 [ 1/n1^2- 1/n2^2]
[ 1/n1^2- 1/n2^2] = 0.048
If we put n1 = 3 and n2 = 4 , [ 1/n1^2- 1/n2^2] = 0.048
For n=4 to n=3 transition, line occurs at 468.9 nm.
Therefore,
nf = 4 and ni = 3
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