Part A Phosgene (carbonyl chloride), COCl2, is an extremely toxic gas that is us
ID: 982956 • Letter: P
Question
Part A
Phosgene (carbonyl chloride), COCl2, is an extremely toxic gas that is used in manufacturing certain dyes and plastics. Phosgene can be produced by reacting carbon monoxide and chlorine gas at high temperatures:
CO(g)+Cl2(g)COCl2(g)
Carbon monoxide and chlorine gas are allowed to react in a sealed vessel at 478 C . At equilibrium, the concentrations were measured and the following results obtained:
What is the equilibrium constant, Kp, of this reaction?
In Part A, you were given the equilibrium pressures, which could be plugged directly into the formula for K. In Part B however, you will be given initial concentrations and only one equilibrium concentration. You must use this data to find all three equilibrium concentrations before you can apply the formula for K.
Part B
The following reaction was performed in a sealed vessel at 740 C :
H2(g)+I2(g)2HI(g)
Initially, only H2 and I2 were present at concentrations of [H2]=3.20M and [I2]=2.85M. The equilibrium concentration of I2 is 0.0100 M . What is the equilibrium constant, Kc, for the reaction at this temperature?
Gas Partial Pressure(atm) CO 0.870 Cl2 1.20 COCl2 0.150
Explanation / Answer
Part A
Kp=p(COCl2)/p(CO) *p(Cl2)
Where p=partial pressure of gases
Kp=(0.150 atm) /(0.870 atm)*(1.20 atm)=0.144 atm^-1
Part B
H2(g)+I2(g)2HI(g)
[H2]=3.20M and [I2]=2.85M. The equilibrium concentration of I2 is 0.0100 M .
Change in conc at equilibrium for I2=x=2.85-0.0100=2.84 M
ICE table
[H2]
[I2]
[HI]
Initial
3.20
2.85
0
change
-2.84
-2.84
+2*2.84=+5.68
equilibrium
3.20-2.84=0.36
2.85-2.84=0.01
5.68
Kc=[HI]^2/[H2] [I2]=(5.68 M)^2/(0.36 M)(0.01 M)=8961.78 (answer)
Kc=8961.78
[H2]
[I2]
[HI]
Initial
3.20
2.85
0
change
-2.84
-2.84
+2*2.84=+5.68
equilibrium
3.20-2.84=0.36
2.85-2.84=0.01
5.68
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.