Lab help My guess was potassium floride, which he said is more than likely corre
ID: 982294 • Letter: L
Question
Lab help My guess was potassium floride, which he said is more than likely correct. I don't understand how to do rows 24-30 Show work pleaseCut | Calibri (Body) 11 -l A+ A Paste Copy A28 :| X v/Interionic Distance (Ang) Format B I U 13 Mass of Vol Flask (g) 14 Mass Of Flask+Unk)(8) 15 Mass Unk (8) 16 Mass of flask +unk+cyclo (g) 17 Mass of cyclo (8) 18 Density of Cyclo (g/mL) 19 Volume of Cyclo (mL) 20 Density of Unk (g/mL) 21 Average Density Unk (g/mL) 22 Volume of unk (mL) 23 24 Molar Mass of Unk (g) 25 Mass of Unit Cell (e) 26 Volume of Unit Cell (mL) 27 Edge Length (Ang) 28 Interionic Clistance (Ang) 29 CI-ions radius from table (Ang) 30 Cation radius from Expt. (Ang) 31 32 27.293 27.293 58.659 61.838 1.36634.545 68.268 70.423 9.609 8.585 0.7780.778 12.3509 11.0347 2.486977 2.480203 14 Mass Of Flask+Unk(8) 2.48359 12.6121 13.9283 Sheet1+ Ready Alkali AlkalineTransition EarthMetal
Explanation / Answer
24. Molar mass of unknown = lets say we have here KCl = 74.55 g
25. Mass of unit cell for FCC = 4 x 74.55/6.023 x 10^23 = 4.95 x 10^-22 g
26. Volume of unit cell = mass/density = 4.95 x 10^-22 g/2.48 g/ml = 2.00 x 10^-22 cm^3
27. Edge length of unit cell = cube.root(2 x 10^-22) = 5.85 x 10^-8 cm = 5.85 Angstrom
28. Interionic distance = 5.85/2 = 2.92 Angstrom
29. Cl- radius = 1.84 Angstrom
30. K+ radius = 2.92 - 1.84 = 1.08 Angstrom
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