1.06 g H2 is allowed to react with 10.4 g N2, producing 2.36 g NH3. Part A What

Question

1.06 g H2 is allowed to react with 10.4 g N2, producing 2.36 g NH3. Part A What is the theoretical yield in grams for this reaction under the given conditions? Express your answer to three significant figures and include the appropriate units.

1.06 g H2 is allowed to react with 10.4 g N2, producing 2.36 g NH3 g Na.producing 2.36 gNHs Part A What is the theoretical yield in grams for this reaction under the given conditions? Express your answer to three significant figures and include the appropriate units. 2 8.57 g Submit Hints My Answers Give Up Review Part Incorrect; Try Again; 5 attempts remaining Part B What is the percent yield for this reaction under the given conditions? Express your answer to three significant figures and include the appropriate units. 2 ValueUnits Submit Hints My Answers Give Up Review Part

Explanation / Answer

N2 + 3 H2 -----> 2 NH3

BASED ON THE GIVEN DATA THE LIMITING REAGENT IS H2

From the balanced eq. 3 g of H2 = 34 g. of NH3

Then, 1.06 g. of H2 = 34X1.06/3 = 12.013 g. of NH3

Therfore theoretical yield = 12.013 g. of ammonia

but calculated yield is 2.36 g.

then , % yeild = 2.36 X 100/12.013 = 19.64 %

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