Kemmi pipets 25.00 mL of pure 1-propanol (C_3H_7OH, a liquid organic alcohol) in

Question

Kemmi pipets 25.00 mL of pure 1-propanol (C_3H_7OH, a liquid organic alcohol) into a 100.0 mL volumetric flask. She dilutes it with water. Help her calculate the strength of her diluted solution. Volumes: 25.00 mL volumetric pipet, 100.00 mL volumetric flask. Molar mass of pure 1-propanol: 60.09 g/mol. Density- of pure 1-propanol: 0.803 g/mL Calculate the number of moles in exactly 25.00 mL of 1-propanol. (3 significant figures; units of mol) Calculate the molarity of the diluted solution. (3 significant figures; units of M or mol/L)

Explanation / Answer

The number of moles you can calculate with the following expression:

moles = m/MW

to get the mass, use the expression of density:

d = m/V ----> m = d*V

If you combine the two above expressions you'll get the following:

moles = d*V / MW

moles = 0.803 g/mL * 25 mL / 60.09 g/mol

moles = 0.334 moles

To get the molarity:

M = moles / V

M = 0.334 moles / 0.1 L = 3.34 M

Hope this helps

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