Figure 3 (shown below) is a cross-sectional diagram illustrating the steady-stat

Question

Figure 3 (shown below) is a cross-sectional diagram illustrating the steady-state positions and conditions of a pond and river relative to a confined aquifer. A chemical company accidentally dumps a conservative (nonreactive) chemical substance into the pond. Assuming that the chemical instantly mixes with the pond water, estimate how long (in days) it would take for the contaminant to get to the river You can reasonably assume that the chemical moves with the water (i.e., it doesn't get adsorbed by the soil). The aquifer properties are theta_s (porosity) = 0 426, b = 18 m, and T = 0 85 m^2 s^-1. The height of the pond surface above the datum (h_p) is 537 m, the height of the river above the datum (h_r) is 531 m, and the length of the aquifer (f) is 7 km.

Explanation / Answer

T = bK , 18 * K=0.85 so K= 0.04722

ne= porosity

Q = - KA dH/neL Q/A =- K dH/neL = V(average linear seepage velocity)

V= -0.04722 * 6 /7000*0.426 = 9.5 * 10^-5 m/s

time taken for contamination =length of aquifier /seepage velocity = 7000/9.5 * 10^-5 s

= 7.368 * 10^7/86400 days

= 852.82 days

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