0.0851 grams of an oil having a heat of combustion of 8.96 kcal per gram, was bu
ID: 978314 • Letter: 0
Question
0.0851 grams of an oil having a heat of combustion of 8.96 kcal per gram, was burned in the Calorimetry setup as used in this experiment. In the can was 125 00 grams of ethylene glycol instead of water. When ignited, the temperature of the ethylene glycol went up by 24.20 degree C. Calculate the heat capacity of the calorimeter system. 0.0575 grams of another oil was then combusted in this calorimeter. The temperature was measured to be 21.84 degree C. Calculate the heat of combustion of the oil.Explanation / Answer
a. heat capacity of calorimeter
= 125+ 0.0851 * 8.96 / 24.90 = 45.01 kcal/ K
b. Heat of combustion of oil.
45.01 * 21.84 /(125 +.0575) = 7.86 kcal / g
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