A reaction occurs when 183.5 grams of acetic acid is reacted with 140.4 grams of

Question

A reaction occurs when 183.5 grams of acetic acid is reacted with 140.4 grams of sodium hydroxide. [CH_3O_2H = 60.05 g/mol| [NaOH = 40.00 g/mol| [CH_3CO_2Na = 82.03 g/mol H_2O = 18.00 g/mol) The reaction is the following: CH_3COOH(aq) + NaOH(aq) rightarrow NaCH_3CO_2(aq) + H_2O(l) Which reactant is the limiting reagent with respect to sodium acetate (NaCH_3CO_2)? How many grains of sodium acetate arc produced in the reaction based on the limiting reagent? If the actual yield is 41.09 grams of sodium acetate-what is the % yield in grams ?

Explanation / Answer

Part a)

CH3COOH(aq) + NaOH(aq)                 CH3COONa(aq) + H2O(l)

According to reaction,

1 mole acetic acid reacts with 1 mole NaOH

i.e; 60g acetic acid reacts with 40g NaOH

so, 183.5g acetic acid will react with (40/60)x183.5=122.33g NaOH

whereas 140.4g NaOH require (60/40)x140.4=210.6g acetic acid

Thus, acetic acid is the limiting reagent as only 183.5g acetic acid is available.

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