A reaction follows the following two-step mechanism. 2A rightarrow A_2 Slow A_2

Question

A reaction follows the following two-step mechanism. 2A rightarrow A_2 Slow A_2 + B rightarrow A_2B Fast Overall: 2A + B = A_2B What is the rate law? Rate =k[A]^2[B] Rate = k[A][B] Rate = k[A_2][B] Rate = k[A]^2 Which of the following statements are true? The equilibrium constant for the forward reaction is equal to the equilibrium constant for the reverse reaction. Dynamic equilibrium indicates that the amount of reactants and products are equal A reaction quotient (Q) larger than the equilibrium constant (K) means that the reaction will favor the production of more products. Dynamic equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction. All of the above are true

Explanation / Answer

11. The rate of reaction depends upon slow step is called rate determing step

Rate = K[A]2

D. Rate = K[A]2

12. At equilibrium rate of farward reaction is equal to rate of back ward reaction

D. At dynamic equilibrium occurs rate of farward reation is equal to rate of revese( back ward )reaction

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