A ray of red light (%u03BB = 700 nm) passing from air (n = 1.00) into water (n =

Question

A ray of red light (%u03BB = 700 nm) passing from air (n = 1.00) into water (n = 1.33) is incident on the water%u2019s surface at an angle of 45 degrees from the normal. Calculate:

a. the angle of the ray from the surface normal in the water. b. the wavelength of light in the water.

An electron and a proton are each traveling (separately) at 125 m/s from right to left through a magnetic field of 2.0 T out of the page. Calculate the magnitude and direction of the magnetic force experienced by:

a. the electron. b. the proton.

Explanation / Answer

1) a) 1*sin(45)= 1.33*sin(theta)

theta = arcsin(sin(45)/1.33)=32.12 degrees

b) wavelength = 700/1.33=526.3 nm

2) both feel same force, F = q v B = 1.6E-19*125*2=4.0E-17

a) direciton is down

b) direciton is up

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