(5pts) A container of volume 22.4 L contains 4.0 mol H2 and 1.0 mol N2 at 273.15

Question

(5pts) A container of volume 22.4 L contains 4.0 mol H2 and 1.0 mol N2 at 273.15K. What is the partial pressure of each gas? What is the total pressure?

(5pts) What is the heat capacity of an object whose temperature rose by 7.36°C when supplied with 167J of energy as heat? b. (2pts) if the object consists of 3.8 moles of material, what is the molar heat capacity of the object?

(5pts) What mass of sodium chloride, NaCl, should be dissolved in enough water to make up 575 mL of 0.75 M NaCl(aq)?

(4pts) What pressure is exerted by a sample of oxygen gas of mass 3.27 g in a container of volume 3.0 l at 35°C?

(3 pts) the volume of a cylinder of oxygen gas (O2) is 45 L. Give the volume in cubic meters and mililiters.

(10pts) Estimate the freezing point of 250ml of water containing 8.5 g calcium hydroxide Al(OH)2

(8pts) Calculate the equilibrium constant for the following reaction (at 25°C)

C2H6(g) + H2(g) --> 2CH4(g)

(5pts) What is the Kinetic Energy of a tennis ball of mass 52 g served at 31 m/s

(10pts)

a.) Determine the rate law relationship

b.) Calculate the value of the rate constant

Initial [A]

Initial Rate

1.0 x10-2

4.0 x 10-2

Initial [A]

Initial Rate

1.0 x10-2

4.0 x 10-2

Explanation / Answer

ANSWER

Dear candidate you have posted too many questions, as per guidelines one question one time. Here we solve first two questions, please send others separtely.

(A) Total pressure can be found by the equation

PV = nRT

P = nRT / V

n = Tota no. of moles =4 + 1 = 5

P = 5 X 8.314 X 273.15 / 22.4 = 506.9 Pa

Partial pressure can be found by mole fraction values

Mole fraction of H2 = moles of H2 / Total moles = 4 / 5 = 0.8

mole fraction of N2 = 1 / 5 = 0.2

Partial pressue of a gas = Mole raction X total pressure

Partial pressure of H2 = 0.8 X 504.9 = 403.92 Pa

Mole fraction of N2 = 0.2 X 504.9 = 100.98 Pa

(B) Heat capacity = energy absorbed / change in temperature = 167 J/ 7.36oC = 22.69J/oC .

Molar heat capacity = energy absorbed / no. of moles = 167 / 3.8 = 43.94J/mol

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