(5c) While sipping a very hot cup of coffee just outside her laboratory, Candy C

Question

(5c) While sipping a very hot cup of coffee just outside her laboratory, Candy Chemist pondered the maximum temperature of sipping hot coffee without burning her lips knowing repeated burns greatly increase the incidence of oral cancer. So, Candy set up an experimen in her coffee cup calorimeter (CCC) Into her CCC, she placed 100.0 g of freshly brewed (press-pot!) coffee at the ideal temperatur for brewing, 93.3°C. She then placed a 100.0 g nugget of aluminum at -111.6°C, for which s = 0.902 J g-1 oC". Determine the final temperature of the coffee. Candy assumed the specific heat capacity of coffee is 4.25 J g oC, and the calorimeter constant is 317 Joc

Explanation / Answer

m = 100 g

Ti = 93.3°C

m = 100 g of alu

Tal = -111.6

Cp = 0.902 J/gC

find final T of coffe

Cp coffe = 4.25

Ccal = 31.7 J/C

Qcalorimeter + Qcoffe = -Qaluminium

Ccalorimeter * (Tf-Ti)+ mass of coffe * Cp coffe * (Tf-Ti) = -mass of aluminium * Cp al * (Tf-Tal)

substitute

31.7*(Tf-93.3) + (100*4.25)(Tf-93.3) = -100*0.902 * (Tf--111.6)

(100*4.25+100*4.25)(Tf-93.3) =- 90.2*(Tf+111.6.)

850*Tf - 93.3*850 = -90.2Tf -10066.32

Tf(850+90.2) = -10066.32+93.3*850

Tf = (69238.68)/(850+90.2)

Tf = 73.64 °C

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