If you have 3.66 g of Al_2 O_3, how many moles do you have? What is Avogadro\'s

Question

If you have 3.66 g of Al_2 O_3, how many moles do you have? What is Avogadro's Number ? You are building cars. The only parts that matter are car bodies, headlights, and tires Body + 2 Headlights + 4 Tires rightarrow l Car You have 16 Bodies, 14 headlights, and 20 Tires. The limiting reactant is. The theoretical yield is. Briefly define the terms: limiting reactant, theoretical yield Perform these conversions. 44.9 mL = L 19 degree = K 729 mm Hg = atm Use the Ideal Gas Law, the values calculated in *4. and R " 0.0821 I. atm/mol K to calculate the number of moles of gas which this data represents. A substance is oxidized when it (gains/loses) electrons, A substance is reduced when it (gains/loses) electrons, In the following reaction, which reactant got reduced? 2 Ag^+_aq) + Cu_(s) rightarrow Cu^+2_(aq) + 2 Ag_(s)

Explanation / Answer

1. With the molecular weight of Al2O3: (27*2) + (3*16) = 102 g/mol
moles = 3.66 / 102 = 0.0359 moles

2. The avogadro number is 6.023x1023 atoms or molecules.

3. The limiting agent is the agent that is in the fewer quantity to react with another. For example, if you need 4 apple and 1 liter of water to make some apple juice, but instead you have 2 apple and 1 Liter of water, means that the apple are in fewer quantities that is needed, so is the limiting starting ingredient.

The theorical yield would be the theorical mass or moles that it will be produced in a reaction basing on the starting reactants (in mass or moles).

Now, in the reaction: B + 2H + 4T -----> C to determine the limiting reagent:
1 B -----> 2 H
16 B -----> X
X = 16*2 = 32 H and we have 14 H, so, the limiting reactant would be the H and the T. now between H and T:
2 H ----> 4 T
14 -----> X
X = 14*4 / 2 = 28 T, and we have 20 T, so the Tire would be the limiting reactant

The theorical yield would be:
4 T ----> 1 C
20 T ----> X
X = 20*1 / 4 = 5 cars.

4. Conversions:
44.9 mL * 1L/1000 mL = 0.0449 L
19 °C + 273 = 292 K
729 mmHg * 1atm/760 mmHg = 0.9592 atm

5. The ideal gas law: PV = nRT ---< n = PV/RT
n = 0.9592 * 0.0449 / 0.0821*292
n = 0.0018 moles

6. A substance is oxidized when it lose electrons, and a substance is reduced when it gains electrons.

7. Ag+ pass to Ag. in other words, from 1+ to 0 in oxidation state. It gained 1 electrons, so, it was reduced.
Cu pass to Cu2+, (From 0 to 2+) it lose 2 electrons, it was oxidized.

Hope this helps

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