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4 37% Tue 8:51 PM Q EE Safari Ed History Bookmarks Window File View Help Northern Virginia Community College, Annandale CHM 111 Spring16 BORING: HW 7 Chapter 7 Concepts & Problems C Reade biscms/mod/ibis/view.php?id 2385145 www.saplinglearning.com/i Matchin... Gotham.. Academi... Surgisil... Virginia... Norther... wwwsa... Match e.. Romper 80% o... Gan My Assignment Resources Yo Attempts Score & 4/19/2016 11:00 PM A 3.9/10 4/19/2016 03:23 PM Grade book Assignme Calculator Periodic Table Available Fr 90 Mave 6 of 10 he Due Date: BRRi uc copy Map enera emIS Late presented by Sapling Lea ld McQuarrie .Peter ARock.Etha submission 00 The energies, E, for the first few states of an unknown element are shown here in arbitrary units. 95 Points Poss Parer Screen Shot 00 0.47 PM Grade Cated16 A gaseous sample of this element is bombarded by photons of various energies (in these same units Match each photon to the result of its absorption (or lack thereof) by an n 1 electron Description Photon Energy Result Policies: The 42 ar n-1 to n-2 You can chec 34 You can view up on an que electro ejecte 24 untit You can keep ot absorbed you get it righ The You lose 5% o ouc... 8 zip in your questi The ansWe Part O Help With creen Sho o Web Help 1.07 PM Previous Give Up & View Solution Check Answer Next Ext The Part C Technica 2016 Sapling Les 207 privacy policy terms of use contact us help partners

Explanation / Answer

Photon A: The energy of the first shell(n=1) is - 42. If we bombard with a photon of energy 42, the total energy of the electron becomes E = - 42 + 42 = 0. Hence the electron is completely ejected from the atom. Hence

Photon A 42 --------> electron ejected.

Photon B: When we bombard a photon B of energy 34, the total energy of the electron becomes

E = - 42 + 34 = - 8, which is the energy of the 3rd shell.

Hence the electron jumps from n = 1 to n = 3.

Photon B 34 --------> n = 1 to n = 3

Photon C: When we bombard a photon C of energy 31, the total energy of the electron becomes

E = - 42 + 31 = - 11

Since E = -11 is the energy of non of the shell, this photon will not be absorbed.

Photon C 31 --------> not absorbed

Photon D: When we bombard a photon D of energy 24, the total energy of the electron becomes

E = - 42 + 24 = - 18, which is the energy of the 2nd shell.

Hence the electron jumps from n = 1 to n = 2.

Photon D 24 --------> n = 1 to n = 2

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