Internal energy change. Delta E = heat + work = Delta H - P Delta V = q - P Delt

Question

Internal energy change. Delta E = heat + work = Delta H - P Delta V = q - P Delta V In a refrigeration system, the refrigerant gas absorbs 21.39 kJ of heat energy while expanding against an external pressure f 0.278 atm from a volume of 0.0423 L to a volume of 1.876 L. What is the internal energy change for the refrigerant gas? A chemical reaction was conducted inside of a piston against a constant applied pressure of 3.64 atm. The volume of the piston expended from 1.465 L to 3.687 L and transferred32.146 kJ of heat energy to the surroundings. What is the energy change of the system? The decomposition of solid potassium chlorate, KClO_3, produces solid potassium chloride, oxygen gas, and heat (Delta H = -42.5 kj/mol of KClO_3). What is the volume of oxygen gas that forms when 15.0 g of KClO_3 decomposes in an expandable reaction chamber? The pressure inside the reaction chamber was 1.25 atm and the temperature was 102.0 degree C. What was the change in internal energy if the initial volume of the reaction chamber was 12.5 mL and atmospheric pressure during the reaction was 0.987 atm^2.

Explanation / Answer

I'll answer only the part a), if you want the others questions, attach them in a new question.

dE=q-PdV

dE=21.39-(0.278*(0.0423-1.876))

dE=21.39kJ+0.509852L.atm

dE=21.39+0.0516607539

dE=21.4416kJ

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