chapter 8 problem 8.35 calculate the final temperature in degrees Celsius for ea
ID: 971884 • Letter: C
Question
chapter 8 problem 8.35
calculate the final temperature in degrees Celsius for each of the following if N and V do not change
A) A sample of xenon at 25 C and 760. mmHg is cooled to give a pressure of 590. mmHg
B) A tank of argon gas with a pressure of 0.950 ATM at -17 C is heated to give a pressure of 1290 Torr
part B
A sample of helium gas a volume of 6.30 L at a pressure of 825 mmHg and a temperature of 22 C
A) what is the pressure of the gas in ATM
when the volume and temperature of the gas sample are changed to 1450 ml and 354 K if the amount of gas is constant
B) when is the pressure of the gas in ATM when the volume and temperature of the gas sample are changed to 2.23 L and 14 C if the amount of gas is constant
C) when is the pressure of the gas in atm
when the volume and temperature of the gas sample are changed to 12.3 L and 48 C if the amount of gas is constant
problem 8.37
A 128 ml bubble of hot gases at 212 C and 1.80 atm is emitted an active volcano
A) what is the final temperature in degrees Celsius of the gas in the bubble outside the volcano if the final volume of the bubble is 134 ml and the pressure is 0.840 atm if the amount of gas does not change.
Explanation / Answer
Part A:
A)Given that: at constant n and V; P1 = 760 mmHg and P2 = 590 mmHg
T1 = 25 oC = 298 K
P1T2 = P2T1
T2 = P2T1/ P1 = (590 mmHg x 298 K)/760 mmHg = 231.34 K
B)Given that: at constant n and V; P1 = 0.95 atm and P2 = 1290 torr = 1.69 atm
T1 = - 17 oC = 256 K
P1T2 = P2T1
T2 = P2T1/ P1 = (1.69 x 256 K)/0.95 atm = 455.41 K
8.37:
V1 = 128 ml
T1 = 212 oC
P1 = 1.80 atm
V2 =134 ml
P2 = 0.840 atm
P1V1/T1 = P2V2/T2
(1.8 x 128)/212oC = (0.84 x 134)/T2
T2 = 103.6 oC
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