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Double displacement reactions: Answer the following questions: Complete the form

ID: 968285 • Letter: D

Question

Double displacement reactions: Answer the following questions:

Complete the formula equation and write the word equations for the reactions given below. formulas AND NAMES MUST BE CORRECT. (Remember is displacement reactions, it can help to write H_2O as HOH) Label each equation as DR (double displacement) or SR (single displacement). The following observations were obtained from individual experiments with HCl: From the list below, choose the reactants that added to HCl would result in the observation.

Explanation / Answer

MgO(s)                    + 2HCl(aq)   ---------> MgCl2(aq)               + H2O(l)

Magnesium oxide + hydrochloric acid --à Magnesium chloride

Double displacement reaction

Mg                     +       2HCl ---------------> H2 +            MgCl2

Magnesium oxide + hydrochloric acid                    Magnesium chloride  

Single displacement reaction

H2SO4 + Zn(OH)2 ---------------à ZnSO4        + 2 H2O

Sulfuric acid + Zinc hydroxide       Zinc sulphate

Double displacement reaction

Sn +        2HCl             ------> SnCl2 +    H2

Tin + hydrochloric acid        Tin(II)chloride   

Single displacement reaction

Cu(OH)2 +                  H2SO4          ---à 2 H2O +    CuSO4

Copper(II) hydroxide + Sulfuric acid                     Copper (II) sulphate

Double displacement reaction

2Na + 2HCl ==> 2NaCl + H2 (g) Test tube felt warm and bubbles of gas

NaOH + HCl --à NaCl + H2O no chnages

Na2CO3 + 2HCl === 2NaCl + H2O + CO2(g) bubbles of gas

CuO(s) + 2 HCl(aq) CuCl2(aq) + H2O(l) no changes

AgNo3(aq) + HCl(aq) = AgCl(s) + HNo3(aq) solid will form

NaNO3 + HCl--> HNO3 + NaCl no changes

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