Given the values of H rxn, S rxn, and T below, determine S univ. A. H rxn= 118 k

Question

Given the values of Hrxn, Srxn, and Tbelow, determine Suniv.

A. Hrxn= 118 kJ , Srxn= 258 J/K , T= 294 K

B. Hrxn= 118 kJ , Srxn= 258 J/K , T= 294 K

C. Hrxn= 118 kJ , Srxn= 258 J/K , T= 294 K .

D. Hrxn= 118 kJ , Srxn= 258 J/K , T= 545 K .

Predict whether or not the reaction in part A will be spontaneous.

Predict whether or not the reaction in part B will be spontaneous.

Predict whether or not the reaction in part C will be spontaneous.

Predict whether or not the reaction in part D will be spontaneous.

Explanation / Answer

We know that

Grxn =Hrxn - TSrxn

A reaction is spontaneous, when Grxn has a negative value.

1 kJ = 1000J

A. Hrxn = 118 kJ , Srxn = 258 J/K , T= 294 K

Grxn =Hrxn - TSrxn

Grxn =-118000 J- (294 K x 258 J/K)

Grxn =-118000 J- 75852 J

Grxn =-193852 J

Hence the reaction is spontaneous.

B. Hrxn= 118 kJ , Srxn= 258 J/K , T= 294 K

Grxn =Hrxn - TSrxn

Grxn =118000 J- [294 K x (-258 J/K)]

Grxn =118000 J+ 75852 J

Grxn =193852 J

Hence the reaction is non-spontaneous.

C. Hrxn= 118 kJ , Srxn= 258 J/K , T= 294 K .

Grxn =Hrxn - TSrxn

Grxn =- 118000 J- [294 K x (- 258 J/K)]

Grxn =- 118000 J+ 75852 J

Grxn =- 42148 J

Hence the reaction is spontaneous.

D. Hrxn= 118 kJ , Srxn= 258 J/K , T= 545 K

Grxn =Hrxn - TSrxn

Grxn =-118000 J- [545 K x (- 258 J/K)]

Grxn =-118000 J+ 140610 J

Grxn =  22610 J

Hence the reaction is non-spontaneous.

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