please show your work and explain how you got the answer in detail. Note- for th

Question

please show your work and explain how you got the answer in detail. Note- for the 2nd question the answer is not 0.56 M

University Science Books presented by Sapling Learni onald McQuarie Peter A. Rock Ethan Gallogly An equilibrium mixture contains 0.400 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the reactants (carbon monoxide and water vapor) in a 1.00-L container. COg) + H2O(g) CO,g) + H 2(g) How many moles of carbon dioxide would have to be added at constant temperature and volume to increase the amount of carbon monoxide to 0.300 mol once equilibrium has been reestablished? Number mol Hiet O Previous G Check Answer e Next- Next

Explanation / Answer

Since it is multi question i answer only first question

Kc = [CO2][H2] / [CO][H2O]
Kc = (0.400)(0.400) / (0.200)(0.200)
Kc = 4


. . . . . . . . . .CO(g) + H20(g) <--> CO2(g) + H2(g)
initial : . . . . . 0.200 . . 0.200 . . . . 0.400+n . . .0.400
change : . . . +0.100 . +0.100 . . . .-0.100 . . . -0.100
equilibrium: . 0.300 . . 0.300 . . . .0.300+n . . . 0.300

Kc = [CO2][H2] / [CO][H2O]
4 = (0.300+n)(0.300) / ((0.300)(0.300))

1.2 = 0.300+n
n = 0.9 mole

moles of carbon dioxide added = 0.9 mole

Kc = [NO]2 / [N2] [O2] = [0.5]2 / [0.2] [0.2] = 6.25

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